Japanese Number Counter
The purpose of this code is to count from 0-9999 in a different language. For this instance, I decided to go with Japanese. The code creates separate outputs based on the number (ex. ones, hundreds, thousands). By following these steps heres a section of the code where I count in the hundreds category:
#include<stdio.h>
void printInJapanese(int number) {
int thousands = (number / 1000) % 10;
int hundreds = (number / 100) % 10;
int tens = (number / 10) % 10;
int ones = number % 10;
...
//hundreds
if (hundreds > 0) {
switch (hundreds) {
case 1: printf("hyaku");
break;
case 2: printf("nihyaku");
break;
case 3: printf("sanpyaku");
break;
case 4: printf("yonhyaku");
break;
case 5: printf("gohyaku");
break;
case 6: printf("rokuhyaku");
break;
case 7: printf("nanahyaku");
break;
case 8: printf("hachihyaku");
break;
case 9: printf("kyuhyaku");
break;
}
}
...
printf("\n");
}
int main() {
for (int i = 1; i <= 9999; i++) {
printf("&4d = ", i);
printInJapanese(i);
}
return 0;
}